Solve for t. 2(t+1)=10 t=

Distribute 2: Distribute the 2 to the terms inside the parentheses. After distributing 2, 2(t + 1) becomes 2t + 2. So, 2t + 2 = 10.Isolate variable term: Isolate the variable term by subtracting 2 from both sides of the equation. 2t + 2 - 2 = 10 - 2 This simplifies to: 2t = 8Solve for t: Solve for t by dividing both sides of the equation by 2. 2t/2 = 8/2 This simplifies to: t = 4

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Solve for $t$ . $\newline$ $2(t+1)=10$ $\newline$ $t=$

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Math Problems

Grade 8

Solve equations with the distributive property

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Q. Solve for

t

\newline

2(t+1)=10

\newline

t=

Distribute $2$ : Distribute the $2$ to the terms inside the parentheses. $\newline$ After distributing $2$ , $2(t + 1)$ becomes $2t + 2$ . $\newline$ So, $2t + 2 = 10$ .
Isolate variable term: Isolate the variable term by subtracting $2$ from both sides of the equation. $\newline$ $2t + 2 - 2 = 10 - 2$ $\newline$ This simplifies to: $\newline$ $2t = 8$
Solve for t: Solve for t by dividing both sides of the equation by $2$ . $\newline$ $\frac{2t}{2} = \frac{8}{2}$ $\newline$ This simplifies to: $\newline$ $t = 4$