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Solve for ss.\newline2 < \frac{s}{-1} + 1

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Q. Solve for ss.\newline2<s1+12 < \frac{s}{-1} + 1
  1. Isolate term with s: Isolate the term with s.\newline2 < \frac{s}{-1} + 1\newline2 - 1 < \frac{s}{-1} + 1 - 1\newline1 < \frac{s}{-1}
  2. Solve for s: Solve for s by multiplying both sides by 1-1, remember to flip the inequality sign.\newline1 \times -1 > \frac{s}{-1} \times -1\newline-1 > s

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