Solve for r.\n2 log_3 (r+1) = 6\nWrite your answer in simplest form.

Divide by 2: First, divide both sides by 2 to isolate the logarithm. \[ \frac{2 \log_3 (r+1)}{2} = \frac{6}{2} \] \[ \log_3 (r+1) = 3 \]Rewrite in Exponential Form: Rewrite the logarithmic equation in exponential form. \[ 3^3 = r+1 \] \[ 27 = r+1 \]Subtract to Solve for r: Subtract 1 from both sides to solve for $ r $. \[ 27 - 1 = r \] \[ r = 26 \]

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Solve for $r$ . $\newline$ $2 \, \log_3 (r+1) = 6$ $\newline$ Write your answer in simplest form.

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Q. Solve for

r

\newline

2 \, \log_3 (r+1) = 6

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Write your answer in simplest form.

Divide by $2$ : First, divide both sides by $2$ to isolate the logarithm. $\newline$ $\frac{2 \log_3 (r+1)}{2} = \frac{6}{2}$ $\newline$ $\log_3 (r+1) = 3$
Rewrite in Exponential Form: Rewrite the logarithmic equation in exponential form. $\newline$ $3^3 = r+1$ $\newline$ $27 = r+1$
Subtract to Solve for r: Subtract $1$ from both sides to solve for $r$ . $\newline$ $27 - 1 = r$ $\newline$ $r = 26$