Solve for q. 8q + 5 ≥ -3 ______

Subtract 5: Subtract 5 from both sides of the inequality to isolate the term with q. 8q + 5 - 5 ≥ -3 - 5 This simplifies to: 8q ≥ -8Divide by 8: Divide both sides of the inequality by 8 to solve for q. 8q / 8 ≥ -8 / 8 This simplifies to: q ≥ -1Check solution: Check the solution to ensure that it makes sense in the context of the original inequality. Substitute q with -1 into the original inequality: 8(-1) + 5 ≥ -3 -8 + 5 ≥ -3 -3 ≥ -3 This is true, so q ≥ -1 is a valid solution to the inequality.

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Solve for $q$ . $\newline$ $8q + 5 \geq -3$

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Math Problems

Grade 8

Solve two-step inequalities

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Q. Solve for

q

\newline

8q + 5 \geq -3

Subtract $5$ : Subtract $5$ from both sides of the inequality to isolate the term with $q$ . $8q + 5 - 5 \geq -3 - 5$ This simplifies to: $8q \geq -8$
Divide by $8$ : Divide both sides of the inequality by $8$ to solve for $q$ . $\frac{8q}{8} \geq \frac{-8}{8}$ This simplifies to: $q \geq -1$
Check solution: Check the solution to ensure that it makes sense in the context of the original inequality. $\newline$ Substitute $q$ with $-1$ into the original inequality: $\newline$ $8(-1) + 5 \geq -3$ $\newline$ $-8 + 5 \geq -3$ $\newline$ $-3 \geq -3$ $\newline$ This is true, so $q \geq -1$ is a valid solution to the inequality.