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Solve for pp. \newline 3 log⁡2(p+4)=93 \, \log_2(p+4)=9. \newlineWrite your answer in simplest form.

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Full solution

Q. Solve for pp. \newline 3 log⁡2(p+4)=93 \, \log_2(p+4)=9. \newlineWrite your answer in simplest form.
  1. Isolate the logarithm: Divide both sides by 33 to isolate the logarithm.\newlinelog⁡2(p+4)=93 \log_2(p+4) = \frac{9}{3} \newlinelog⁡2(p+4)=3 \log_2(p+4) = 3
  2. Rewrite in exponential form: Rewrite the logarithmic equation in exponential form.\newline23=p+4 2^3 = p + 4 \newline8=p+4 8 = p + 4
  3. Solve for p: Subtract 44 from both sides to solve for p p .\newline8−4=p 8 - 4 = p \newlinep=4 p = 4

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