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Solve for pp.\newline2p1=12p - 1 = 1\newlinep=p = _____\_\_\_\_\_

Full solution

Q. Solve for pp.\newline2p1=12p - 1 = 1\newlinep=p = _____\_\_\_\_\_
  1. Add 11 to isolate term: Add 11 to both sides to isolate the term with pp. \newline2p1+1=1+12p - 1 + 1 = 1 + 1\newline2p=22p = 2
  2. Divide both sides by 22: Divide both sides by 22 to solve for pp.2p2=22\frac{2p}{2} = \frac{2}{2}p=1p = 1