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Solve for p. \newline23p=89\frac{2}{3}p = \frac{8}{9} \newlinep=p=\square

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Q. Solve for p. \newline23p=89\frac{2}{3}p = \frac{8}{9} \newlinep=p=\square
  1. Isolate variable p: Isolate the variable pp by multiplying both sides of the equation by the reciprocal of 23\frac{2}{3}. To isolate pp, we multiply both sides by 32\frac{3}{2}: \left(\frac{\(2\)}{\(3\)}\right)p \times \left(\frac{\(3\)}{\(2\)}\right) = \left(\frac{\(8\)}{\(9\)}\right) \times \left(\frac{\(3\)}{\(2\)}\right)
  2. Perform multiplication: Perform the multiplication on both sides.\(\newlineOn the left side, (23)×(32)=1(\frac{2}{3}) \times (\frac{3}{2}) = 1, so we are left with pp.\newlineOn the right side, (89)×(32)=(8×39×2)=2418(\frac{8}{9}) \times (\frac{3}{2}) = (\frac{8 \times 3}{9 \times 2}) = \frac{24}{18}.
  3. Simplify fraction: Simplify the fraction on the right side. \newline2418\frac{24}{18} can be simplified by dividing both numerator and denominator by 66, which gives us 43\frac{4}{3}.\newlineSo, p=43p = \frac{4}{3}.