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Solve for 
n :

{:[22+n=-12],[n=◻]:}

Solve for n n :\newline22+n=12n= \begin{array}{l} 22+n=-12 \\ n=\square \end{array}

Full solution

Q. Solve for n n :\newline22+n=12n= \begin{array}{l} 22+n=-12 \\ n=\square \end{array}
  1. Isolate variable nn: Isolate the variable nn in the first equation 22+n=1222 + n = -12.
    22+n=1222 + n = -12
    22+n22=122222 + n - 22 = -12 - 22
    n=34n = -34

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