Solve for k. {:[(k)/(6)=(4)/(3)],[k=◻]:}

Isolate k in first equation: Solve the first equation for k. We have the equation (k/6) = (4/3). To solve for k, we need to isolate k on one side of the equation. We can do this by multiplying both sides of the equation by 6 to get rid of the denominator on the left side. So, k = (4/3) * 6Find value of k: Perform the multiplication to find the value of k. Now we multiply 4 by 6 and then divide by 3 to find k. k = (4 * 6) / 3 k = 24 / 3 k = 8Check solution in second equation: Check the solution in the second equation. The second equation is simply k = ◻, which means k should be equal to the value we found. Since we found k = 8, this satisfies the second equation.

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Grade 8

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Q. Solve for

k

\begin{array}{l}\frac{k}{6}=\frac{4}{3} \\k=\square\end{array}

Isolate $k$ in first equation: Solve the first equation for $k$ . We have the equation $\frac{k}{6} = \frac{4}{3}$ . To solve for $k$ , we need to isolate $k$ on one side of the equation. We can do this by multiplying both sides of the equation by $6$ to get rid of the denominator on the left side. So, $k = \frac{4}{3} \times 6$
Find value of k: Perform the multiplication to find the value of k. $\newline$ Now we multiply $4$ by $6$ and then divide by $3$ to find $k$ . $\newline$ $k = (4 \times 6) / 3$ $\newline$ $k = 24 / 3$ $\newline$ $k = 8$
Check solution in second equation: Check the solution in the second equation. $\newline$ The second equation is simply $k = \square$ , which means $k$ should be equal to the value we found. Since we found $k = 8$ , this satisfies the second equation.