Solve for k. {:[(k)/(4)=(3)/(8)],[k=◻]:}

Analyze Equations: Analyze the given system of equations. We have a system of two equations: 1. (k/4) = (3/8) 2. k = ◻ We need to find the value of k that satisfies both equations. Since the second equation is incomplete, we will focus on the first equation to find the value of k.Solve for k: Solve the first equation for k. We have (k/4) = (3/8). To find k, we need to isolate it on one side of the equation. We can do this by multiplying both sides of the equation by 4. k = (3/8) * 4Perform Multiplication: Perform the multiplication to find the value of k. k = 3 * (4/8) k = 3 * 1/2 k = 3/2Check Value of k: Check if the value of k satisfies the second equation. Since the second equation is incomplete and just states k = ◻, we cannot check the value of k against it. However, we have found the value of k that satisfies the first equation.

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Solve for $k$ . $\frac{k}{4}=\frac{3}{8}$ $\newline$ $k=\square$

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Q. Solve for

k

\frac{k}{4}=\frac{3}{8}

\newline

k=\square

Analyze Equations: Analyze the given system of equations. $\newline$ We have a system of two equations: $\newline$ $1$ . $\frac{k}{4} = \frac{3}{8}$ $\newline$ $2$ . $k = \square$ $\newline$ We need to find the value of $k$ that satisfies both equations. Since the second equation is incomplete, we will focus on the first equation to find the value of $k$ .
Solve for k: Solve the first equation for k. $\newline$ We have $(\frac{k}{4}) = (\frac{3}{8})$ . To find $k$ , we need to isolate it on one side of the equation. We can do this by multiplying both sides of the equation by $4$ . $\newline$ $k = (\frac{3}{8}) \times 4$
Perform Multiplication: Perform the multiplication to find the value of $k$ . $k = 3 \times (\frac{4}{8})$ $k = 3 \times \frac{1}{2}$ $k = \frac{3}{2}$
Check Value of $k$ : Check if the value of $k$ satisfies the second equation. $\newline$ Since the second equation is incomplete and just states $k = \square$ , we cannot check the value of $k$ against it. However, we have found the value of $k$ that satisfies the first equation.