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Solve for 
k.

{:[(5k-2)/(3k)=7],[k=]:}

Solve for k k .\newline5k23k=7k= \begin{array}{l} \frac{5 k-2}{3 k}=7 \\ k= \end{array}

Full solution

Q. Solve for k k .\newline5k23k=7k= \begin{array}{l} \frac{5 k-2}{3 k}=7 \\ k= \end{array}
  1. Set up equation: Set up the equation from the given problem.\newline(5k2)/(3k)=7(5k - 2) / (3k) = 7
  2. Multiply by 3k3k: Multiply both sides of the equation by 3k3k to eliminate the denominator.\newline3k×(5k23k)=3k×73k \times \left(\frac{5k - 2}{3k}\right) = 3k \times 7
  3. Simplify equation: Simplify both sides of the equation. 5k2=21k5k - 2 = 21k
  4. Subtract 5k5k: Subtract 5k5k from both sides to get all kk terms on one side.\newline5k5k2=21k5k5k - 5k - 2 = 21k - 5k
  5. Combine like terms: Simplify the equation by combining like terms. 2=16k-2 = 16k
  6. Divide by 1616: Divide both sides by 1616 to solve for kk.k=216k = \frac{-2}{16}
  7. Simplify fraction: Simplify the fraction to find the value of kk.k=18k = -\frac{1}{8}