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Let’s check out your problem:
Solve for
k
k
k
.
\newline
5
k
−
2
3
k
=
7
k
=
\begin{array}{l} \frac{5 k-2}{3 k}=7 \\ k= \end{array}
3
k
5
k
−
2
=
7
k
=
View step-by-step help
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Math Problems
Grade 6
Multiply two decimals: where does the decimal point go?
Full solution
Q.
Solve for
k
k
k
.
\newline
5
k
−
2
3
k
=
7
k
=
\begin{array}{l} \frac{5 k-2}{3 k}=7 \\ k= \end{array}
3
k
5
k
−
2
=
7
k
=
Set up equation:
Set up the equation from the given problem.
\newline
(
5
k
−
2
)
/
(
3
k
)
=
7
(5k - 2) / (3k) = 7
(
5
k
−
2
)
/
(
3
k
)
=
7
Multiply by
3
k
3k
3
k
:
Multiply both sides of the equation by
3
k
3k
3
k
to eliminate the denominator.
\newline
3
k
×
(
5
k
−
2
3
k
)
=
3
k
×
7
3k \times \left(\frac{5k - 2}{3k}\right) = 3k \times 7
3
k
×
(
3
k
5
k
−
2
)
=
3
k
×
7
Simplify equation:
Simplify both sides of the equation.
5
k
−
2
=
21
k
5k - 2 = 21k
5
k
−
2
=
21
k
Subtract
5
k
5k
5
k
:
Subtract
5
k
5k
5
k
from both sides to get all
k
k
k
terms on one side.
\newline
5
k
−
5
k
−
2
=
21
k
−
5
k
5k - 5k - 2 = 21k - 5k
5
k
−
5
k
−
2
=
21
k
−
5
k
Combine like terms:
Simplify the equation by combining like terms.
−
2
=
16
k
-2 = 16k
−
2
=
16
k
Divide by
16
16
16
:
Divide both sides by
16
16
16
to solve for
k
k
k
.
k
=
−
2
16
k = \frac{-2}{16}
k
=
16
−
2
Simplify fraction:
Simplify the
fraction
to find the value of
k
k
k
.
k
=
−
1
8
k = -\frac{1}{8}
k
=
−
8
1
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Question
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0.5
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=
?
0.5 \times 5 = ?
0.5
×
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=
?
\newline
Choices:
\newline
(A)
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0.025
\newline
(B)
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\newline
(C)
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\newline
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