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Solve for 
k.

{:[(3)/(2k)=5],[k=]:}

Solve for k k .\newline32k=5k= \begin{array}{l} \frac{3}{2 k}=5 \\ k= \end{array}

Full solution

Q. Solve for k k .\newline32k=5k= \begin{array}{l} \frac{3}{2 k}=5 \\ k= \end{array}
  1. Isolate kk in the equation: To find the value of kk, we need to solve the equation 32k=5\frac{3}{2k} = 5. We can start by isolating kk on one side of the equation. To do this, we can multiply both sides of the equation by 2k2k to get rid of the fraction.
  2. Multiply both sides by 2k2k: Multiplying both sides of the equation by 2k2k gives us 3=5×2k3 = 5 \times 2k. This simplifies the equation and gets rid of the fraction.
  3. Simplify the equation: Now we have 3=10k3 = 10k. To solve for kk, we need to divide both sides of the equation by 1010.
  4. Divide both sides by 1010: Dividing both sides by 1010 gives us k=310k = \frac{3}{10}. This is the value of kk that satisfies the equation 32k=5\frac{3}{2k} = 5.