Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve for jj.\newline2j+1=32j + 1 = 3\newlinej=____j = \_\_\_\_

Full solution

Q. Solve for jj.\newline2j+1=32j + 1 = 3\newlinej=____j = \_\_\_\_
  1. Subtract 11 to isolate jj: Subtract 11 from both sides to isolate the term with jj.2j+11=312j + 1 - 1 = 3 - 12j=22j = 2
  2. Divide by 22 to solve: Divide both sides by 22 to solve for jj.2j2=22\frac{2j}{2} = \frac{2}{2}j=1j = 1