Solve for h. 4h + 1 ≤ -3 ______

Subtract 1 to isolate h: Subtract 1 from both sides of the inequality to isolate the term with h. 4h + 1 - 1 ≤ -3 - 1 This simplifies to: 4h ≤ -4Divide by 4 for h: Divide both sides of the inequality by 4 to solve for h. 4h / 4 ≤ -4 / 4 This simplifies to: h ≤ -1Check solution: Check the solution by substituting h back into the original inequality to ensure it makes the inequality true. 4(-1) + 1 ≤ -3 -4 + 1 ≤ -3 -3 ≤ -3 Since -3 is equal to -3, the inequality holds true.

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Solve for $h$ . $4h + 1 \leq -3$

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Math Problems

Grade 8

Solve two-step inequalities

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Q. Solve for

h

4h + 1 \leq -3

Subtract $1$ to isolate h: Subtract $1$ from both sides of the inequality to isolate the term with $h$ . $4h + 1 - 1 \leq -3 - 1$ This simplifies to: $4h \leq -4$
Divide by $4$ for h: Divide both sides of the inequality by $4$ to solve for h. $\newline$ $\frac{4h}{4} \leq \frac{-4}{4}$ $\newline$ This simplifies to: $\newline$ $h \leq -1$
Check solution: Check the solution by substituting $h$ back into the original inequality to ensure it makes the inequality true. $4(-1) + 1 \leq -3$ $-4 + 1 \leq -3$ $-3 \leq -3$ Since $-3$ is equal to $-3$ , the inequality holds true.