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Solve for dd.\newline5=3+2d5 = 3 + 2d\newlined=d = _____

Full solution

Q. Solve for dd.\newline5=3+2d5 = 3 + 2d\newlined=d = _____
  1. Subtract 33 to isolate dd: Subtract 33 from both sides to isolate the term with dd.53=3+2d35 - 3 = 3 + 2d - 32=2d2 = 2d
  2. Divide by 22 to solve: Divide both sides by 22 to solve for dd.22=2d2\frac{2}{2} = \frac{2d}{2}1=d1 = d