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Solve for d.d. \newline2(d+2)=182(d + 2) = 18 \newlined=d=\square

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Q. Solve for d.d. \newline2(d+2)=182(d + 2) = 18 \newlined=d=\square
  1. Distribute 22: Distribute the 22 across the parentheses.\newlineWe need to apply the distributive property to remove the parentheses. This means we multiply 22 by each term inside the parentheses (dd and 22).\newlineCalculation: 2(d+2)=2d+22=2d+42(d + 2) = 2\cdot d + 2\cdot 2 = 2d + 4
  2. Set up equation: Set up the equation without the parentheses.\newlineNow that we have distributed the 22, we can write the equation without the parentheses.\newlineEquation: 2d+4=182d + 4 = 18
  3. Subtract 44: Subtract 44 from both sides of the equation to isolate the term with dd. We want to get dd by itself on one side of the equation, so we need to remove the 44 from the left side. Calculation: 2d+44=1842d + 4 - 4 = 18 - 4, which simplifies to 2d=142d = 14
  4. Divide to solve: Divide both sides of the equation by 22 to solve for dd. To find the value of dd, we divide both sides of the equation by 22. Calculation: 2d2=142\frac{2d}{2} = \frac{14}{2}, which simplifies to d=7d = 7