Solve for c. c/3 ≥ 2 ______

Multiply by 3: We are given the inequality c/3 ≥ 2. To solve for c, we need to isolate c on one side of the inequality. We can do this by multiplying both sides of the inequality by 3, which is the denominator of the fraction on the left side. c/3 * 3 ≥ 2 * 3Perform multiplication: Perform the multiplication on both sides of the inequality. c ≥ 6Check solution: Check the solution to ensure that it makes sense in the context of the original inequality. If we substitute c with a number greater than or equal to 6 back into the original inequality, it should make the inequality true. Let's test c = 6: (6)/3 ≥ 2 2 ≥ 2 This is true, so our solution seems correct.Conclude solution: Since there are no restrictions on c other than it being greater than or equal to 6, we can conclude that the solution to the inequality c/3 ≥ 2 is c ≥ 6.

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Solve for $c$ . $\newline$ $\frac{c}{3} \geq 2$

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Grade 8

Solve one-step inequalities

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Q. Solve for

c

\newline

\frac{c}{3} \geq 2

Multiply by $3$ : We are given the inequality $\frac{c}{3} \geq 2$ . To solve for $c$ , we need to isolate $c$ on one side of the inequality. We can do this by multiplying both sides of the inequality by $3$ , which is the denominator of the fraction on the left side. $\newline$ $\frac{c}{3} \times 3 \geq 2 \times 3$
Perform multiplication: Perform the multiplication on both sides of the inequality. $c \geq 6$
Check solution: Check the solution to ensure that it makes sense in the context of the original inequality. If we substitute $c$ with a number greater than or equal to $6$ back into the original inequality, it should make the inequality true. $\newline$ Let's test $c = 6$ : $\newline$ $\frac{6}{3} \geq 2$ $\newline$ $2 \geq 2$ $\newline$ This is true, so our solution seems correct.
Conclude solution: Since there are no restrictions on $c$ other than it being greater than or equal to $6$ , we can conclude that the solution to the inequality $\frac{c}{3} \geq 2$ is $c \geq 6$ .