Solve for c. {:[(8)/(3)c-2=(2)/(3)c-12],[c=]:}

Isolate variable terms: Isolate the variable terms on one side for the equation (8/3)c - 2 = (2/3)c - 12. We can start by subtracting (2/3)c from both sides to get all the c terms on one side. (8/3)c - (2/3)c - 2 = (2/3)c - (2/3)c - 12 (8/3)c - (2/3)c = -2 + 12Combine like terms: Combine like terms on both sides of the equation. (8/3)c - (2/3)c = 10 (6/3)c = 10 Simplify (6/3)c to 2c. 2c = 10Solve for c: Solve for c by dividing both sides by 2. 2c / 2 = 10 / 2 c = 5

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Math Problems

Algebra 1

Solve linear equations with variables on both sides

Full solution

Q. Solve for

c

\newline

\begin{array}{l} \frac{8}{3} c-2=\frac{2}{3} c-12 \\ c=\square \end{array}

Isolate variable terms: Isolate the variable terms on one side for the equation $(\frac{8}{3})c - 2 = (\frac{2}{3})c - 12$ . We can start by subtracting $(\frac{2}{3})c$ from both sides to get all the $c$ terms on one side. $(\frac{8}{3})c - (\frac{2}{3})c - 2 = (\frac{2}{3})c - (\frac{2}{3})c - 12$ $(\frac{8}{3})c - (\frac{2}{3})c = -2 + 12$
Combine like terms: Combine like terms on both sides of the equation. $\newline$ $(\frac{8}{3})c - (\frac{2}{3})c = 10$ $\newline$ $(\frac{6}{3})c = 10$ $\newline$ Simplify $(\frac{6}{3})c$ to $2c$ . $\newline$ $2c = 10$
Solve for c: Solve for c by dividing both sides by $2$ . $\newline$ $\frac{2c}{2} = \frac{10}{2}$ $\newline$ $c = 5$