Solve for c. 8 − 2c = –10 c = _____

Move Constant Term: Isolate the variable term, -2c, by moving the constant term to the other side of the equation. 8 − 2c = –10 To isolate -2c, subtract 8 from both sides. 8 − 2c − 8 = –10 − 8 -2c = -18Isolate Variable Term: Solve for c by dividing both sides of the equation by -2. -2c = -18 To isolate c, divide both sides by -2. (-2c)/(-2) = -18/(-2) c = 9

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Solve for $c$ . $\newline$ $8 - 2c = -10$ $\newline$ $c =$ $\_\_\_\_\_$

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Grade 8

Solve equations: mixed review

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Q. Solve for

c

\newline

8 - 2c = -10

\newline

c =

\_\_\_\_\_

Move Constant Term: Isolate the variable term, $-2c$ , by moving the constant term to the other side of the equation. $\newline$ $8 - 2c = -10$ $\newline$ To isolate $-2c$ , subtract $8$ from both sides. $\newline$ $8 - 2c - 8 = -10 - 8$ $\newline$ $-2c = -18$
Isolate Variable Term: Solve for $c$ by dividing both sides of the equation by $-2$ . $-2c = -18$ To isolate $c$ , divide both sides by $-2$ . $\frac{-2c}{-2} = \frac{-18}{-2}$ $c = 9$