Solve for c. 4c - 3c = 14 c = ____

Combine Like Terms: Combine like terms on the left side of the equation. We have 4c and -3c, which are like terms because they both contain the variable c. To combine them, we subtract 3c from 4c because of the minus sign in front of 3c. The calculation is 4c - 3c = c.Rewrite Equation: Rewrite the equation with the combined terms. After combining like terms, the equation becomes c = 14.Check Balance: Check if the equation is balanced. To check if the equation is balanced, we can substitute the value of c back into the original equation. Substituting c = 14 into 4c - 3c gives us 4(14) - 3(14) = 14. This simplifies to 56 - 42 = 14, which is true since 14 = 14.

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Math Problems

Grade 7

Solve equations involving like terms

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Q. Solve for

c

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4c - 3c = 14

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c = ____

Combine Like Terms: Combine like terms on the left side of the equation. $\newline$ We have $4c$ and $-3c$ , which are like terms because they both contain the variable $c$ . $\newline$ To combine them, we subtract $3c$ from $4c$ because of the minus sign in front of $3c$ . $\newline$ The calculation is $4c - 3c = c$ .
Rewrite Equation: Rewrite the equation with the combined terms. $\newline$ After combining like terms, the equation becomes $c = 14$ .
Check Balance: Check if the equation is balanced. $\newline$ To check if the equation is balanced, we can substitute the value of $c$ back into the original equation. $\newline$ Substituting $c = 14$ into $4c - 3c$ gives us $4(14) - 3(14) = 14$ . $\newline$ This simplifies to $56 - 42 = 14$ , which is true since $14 = 14$ .