Solve for c. 4.2=-0.3-(c)/( 0.4) Answer: c=

Write Equation: Write down the equation. 4.2 = -0.3 - (c / 0.4) We need to solve for c.Isolate Term: Isolate the term containing c. To do this, we will add 0.3 to both sides of the equation to move the constant term from the right side to the left side. 4.2 + 0.3 = -0.3 + 0.3 - (c / 0.4)Perform Addition: Perform the addition on both sides. 4.5 = 0 - (c / 0.4) Now, we have 4.5 = - (c / 0.4).Get Rid of Negative Sign: To get rid of the negative sign, we can multiply both sides by -1. -4.5 = c / 0.4Multiply by -1: Now, we need to solve for c by getting rid of the denominator 0.4. We can do this by multiplying both sides of the equation by 0.4. -4.5 * 0.4 = (c / 0.4) * 0.4Solve for c: Perform the multiplication on both sides. -1.8 = c We have found the value of c.

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Solve for
c.

4.2=-0.3-(c)/( 0.4)
Answer:
c=

Solve for $c$ . $\newline$ $4.2=-0.3-\frac{c}{0.4}$ $\newline$ Answer: $c=$

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Math Problems

Grade 6

Solve one-step addition and subtraction equations with decimals and fractions

Full solution

Q. Solve for

c

\newline

4.2=-0.3-\frac{c}{0.4}

\newline

Answer:

c=

Write Equation: Write down the equation. $\newline$ $4.2 = -0.3 - \frac{c}{0.4}$ $\newline$ We need to solve for $c$ .
Isolate Term: Isolate the term containing $c$ . To do this, we will add $0.3$ to both sides of the equation to move the constant term from the right side to the left side. $4.2 + 0.3 = -0.3 + 0.3 - \left(\frac{c}{0.4}\right)$
Perform Addition: Perform the addition on both sides. $\newline$ $4.5 = 0 - \frac{c}{0.4}$ $\newline$ Now, we have $4.5 = - \frac{c}{0.4}$ .
Get Rid of Negative Sign: To get rid of the negative sign, we can multiply both sides by -1＂).$\newline\$-4.5 = \frac{c}{0.4}$
Multiply by $-1$: Now, we need to solve for $c$ by getting rid of the denominator $0.4$. We can do this by multiplying both sides of the equation by $0.4$.$\newline$$-4.5 \times 0.4 = \left(\frac{c}{0.4}\right) \times 0.4$
Solve for $c$: Perform the multiplication on both sides.$-1.8 = c$ We have found the value of $c$.