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$Solve for b. Express your answer as a proper or improper fraction in simplest terms. (2)/(3)=-(1)/(10)b+(2)/(3) Answer: b=$

Solve for $b$ . Express your answer as a proper or improper fraction in simplest terms. $\newline$ $\frac{2}{3}=-\frac{1}{10} b+\frac{2}{3}$ $\newline$ Answer: $b=$

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Find the roots of factored polynomials

Full solution

Q. Solve for

b

. Express your answer as a proper or improper fraction in simplest terms.

\newline

\frac{2}{3}=-\frac{1}{10} b+\frac{2}{3}

\newline

Answer:

b=

Write Equation: First, let's write down the equation we need to solve: $\newline$ rac{2}{3} = -rac{1}{10}b + rac{2}{3}
Simplify by Subtracting: We notice that $(\frac{2}{3})$ appears on both sides of the equation. To simplify, we can subtract $(\frac{2}{3})$ from both sides to eliminate it: $(\frac{2}{3}) - (\frac{2}{3}) = -(\frac{1}{10})b + (\frac{2}{3}) - (\frac{2}{3})$
Solve for $b$ : After subtracting $\frac{2}{3}$ from both sides, we get: $\newline$ $0 = -\frac{1}{10}b$
Isolate b: Now, we need to solve for b. Since $-(\frac{1}{10})b = 0$ , we can divide both sides by $-(\frac{1}{10})$ to isolate b: $\newline$ $\frac{0}{-(\frac{1}{10})} = b$
Final Answer: Dividing $0$ by any non-zero number is still $0$ , so we have: $\newline$ $b = 0$

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