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Solve for bb.\newlineb72|b| - 7 \leq 2\newlineWrite a compound inequality like 1 < x < 3 or like x < 1 or x > 3. Use integers, proper fractions, or improper fractions in simplest form.\newline______

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Q. Solve for bb.\newlineb72|b| - 7 \leq 2\newlineWrite a compound inequality like 1<x<31 < x < 3 or like x<1x < 1 or x>3x > 3. Use integers, proper fractions, or improper fractions in simplest form.\newline______
  1. Isolate absolute value: We have the inequality: \newlineb72|b| - 7 \leq 2\newlineFirst, we need to isolate the absolute value term b|b| on one side of the inequality.
  2. Add 77: Add 77 to both sides of the inequality to isolate b|b|: \newlineb7+72+7|b| - 7 + 7 \leq 2 + 7\newlineb9|b| \leq 9
  3. Consider absolute value definition: Now we need to consider the definition of absolute value, which states that |b|\(\newline) is the distance of b\(\newline) from \(0\newline) on the number line. The inequality |b| \leq \(9\newline) means that b\(\newline) is within a distance of \(9\newline) from \(0\newline). This gives us two scenarios: b \leq \(9\newline) and b \geq \(-9\newline).
  4. Translate into compound inequality: Translate the definition of absolute value into a compound inequality:\newlineb9-b \leq 9 and b9b \leq 9\newlineSince b9-b \leq 9 is equivalent to b9b \geq -9, we can write the compound inequality as:\newline9b9-9 \leq b \leq 9

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