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Solve for 
b.

(3)/(8)b+9=36
Answer: 
b=

Solve for b b .\newline38b+9=36 \frac{3}{8} b+9=36 \newlineAnswer: b= b=

Full solution

Q. Solve for b b .\newline38b+9=36 \frac{3}{8} b+9=36 \newlineAnswer: b= b=
  1. Subtract 99: Subtract 99 from both sides of the equation to isolate the term containing bb. We start with the equation 38b+9=36\frac{3}{8}b + 9 = 36. To isolate the term with bb, we need to get rid of the constant term on the same side as bb, which is 99. We do this by subtracting 99 from both sides of the equation. 38b+99=369\frac{3}{8}b + 9 - 9 = 36 - 9 This simplifies to: 38b=27\frac{3}{8}b = 27
  2. Multiply by reciprocal: Multiply both sides of the equation by the reciprocal of (38)(\frac{3}{8}) to solve for bb. Now we have (38)b=27(\frac{3}{8})b = 27. To solve for bb, we need to get rid of the fraction (38)(\frac{3}{8}) that is multiplied by bb. We do this by multiplying both sides of the equation by the reciprocal of (38)(\frac{3}{8}), which is (83)(\frac{8}{3}). (38)b×(83)=27×(83)(\frac{3}{8})b \times (\frac{8}{3}) = 27 \times (\frac{8}{3}) This simplifies to: b=27×(83)b = 27 \times (\frac{8}{3})
  3. Calculate value: Calculate the value of bb.\newlineNow we perform the multiplication on the right side of the equation.\newlineb=27×(8/3)b = 27 \times (8/3)\newlineb=(27/1)×(8/3)b = (27/1) \times (8/3)\newlineb=(27×8)/3b = (27 \times 8) / 3\newlineb=216/3b = 216 / 3\newlineb=72b = 72