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Solve for bb.\newline2=3b12 = 3b - 1\newlineb=b = _____

Full solution

Q. Solve for bb.\newline2=3b12 = 3b - 1\newlineb=b = _____
  1. Add 11 to isolate bb: Add 11 to both sides to isolate the term with bb on one side.\newlineCalculation: 2+1=3b1+12 + 1 = 3b - 1 + 1\newlineResult: 3=3b3 = 3b
  2. Divide by 33 to solve: Divide both sides by 33 to solve for bb.\newlineCalculation: 33=3b3\frac{3}{3} = \frac{3b}{3}\newlineResult: 1=b1 = b