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Solve for all values of 
x.

(x-7)/(x-3)=(-2)/(x)
Answer: 
x=

Solve for all values of x x .\newlinex7x3=2x \frac{x-7}{x-3}=\frac{-2}{x} \newlineAnswer: x= x=

Full solution

Q. Solve for all values of x x .\newlinex7x3=2x \frac{x-7}{x-3}=\frac{-2}{x} \newlineAnswer: x= x=
  1. Set Up Equation: First, we need to set up the equation given by the problem: (x7)/(x3)=(2)/x(x-7)/(x-3) = (-2)/x. To solve for xx, we will cross-multiply to eliminate the fractions.
  2. Cross-Multiply: Cross-multiplying gives us: x - \(7) * x = (2-2) * (x - 33)\. This will allow us to create a quadratic equation.
  3. Expand Equation: Expanding both sides of the equation, we get: x27x=2x+6x^2 - 7x = -2x + 6. This simplifies the equation and prepares it for further manipulation.
  4. Move Terms: Next, we will move all terms to one side of the equation to set it equal to zero: x27x+2x6=0x^2 - 7x + 2x - 6 = 0.
  5. Factor Quadratic: Combining like terms, we get: x25x6=0x^2 - 5x - 6 = 0. This is the quadratic equation we need to solve for xx.
  6. Set Equal to Zero: To solve the quadratic equation, we can factor it: (x6)(x+1)=0(x - 6)(x + 1) = 0.
  7. Solve for xx: Setting each factor equal to zero gives us the potential solutions for xx: x6=0x - 6 = 0 or x+1=0x + 1 = 0.
  8. Check Solutions: Solving each equation for xx gives us the solutions: x=6x = 6 or x=1x = -1.
  9. Check x=6x = 6: However, we must check these solutions against the original equation to ensure they do not make any denominator equal to zero, as that would be undefined.
  10. Check x=1x = -1: Checking x=6x = 6: The original equation's denominators are (63)(6 - 3) and 66, neither of which is zero, so x=6x = 6 is a valid solution.
  11. Check x=1x = -1: Checking x=6x = 6: The original equation's denominators are (63)(6 - 3) and 66, neither of which is zero, so x=6x = 6 is a valid solution.Checking x=1x = -1: The original equation's denominators are (13)(-1 - 3) and 1-1, neither of which is zero, so x=1x = -1 is also a valid solution.

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