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Solve for all values of 
x.

(x-5)/(x+9)=(4)/(x)
Answer: 
x=

Solve for all values of x x .\newlinex5x+9=4x \frac{x-5}{x+9}=\frac{4}{x} \newlineAnswer: x= x=

Full solution

Q. Solve for all values of x x .\newlinex5x+9=4x \frac{x-5}{x+9}=\frac{4}{x} \newlineAnswer: x= x=
  1. Identify Equation: First, we need to identify the equation we are solving: (x5)/(x+9)=(4)/(x)(x-5)/(x+9)=(4)/(x). We want to find all values of xx that satisfy this equation.
  2. Cross-Multiply to Eliminate Fractions: To solve the equation, we will cross-multiply to eliminate the fractions: x - \(5) \times x = 44 \times (x + 99)\
  3. Distribute and Simplify: Now, we distribute on both sides of the equation: x25x=4x+36x^2 - 5x = 4x + 36.
  4. Bring Terms Together: Next, we bring all terms to one side to set the equation to zero: x25x4x36=0x^2 - 5x - 4x - 36 = 0.
  5. Factor or Use Quadratic Formula: Combine like terms: x29x36=0x^2 - 9x - 36 = 0.
  6. Set Factors Equal to Zero: Now, we need to factor the quadratic equation, if possible, or use the quadratic formula to find the values of xx. Let's try to factor first: (x12)(x+3)=0(x - 12)(x + 3) = 0.
  7. Solve for x: We set each factor equal to zero and solve for x: x12=0x - 12 = 0 or x+3=0x + 3 = 0.
  8. Check for Extraneous Solutions: Solving the first equation gives us x=12x = 12. Solving the second equation gives us x=3x = -3.
  9. Check x=12x = 12: However, we must check for extraneous solutions by plugging these values back into the original equation, because the original equation has restrictions on the values of xx (xx cannot be 00 or 9-9, as these would make the denominators zero).
  10. Check x=3x = -3: Checking x=12x = 12: 12512+9=721=13\frac{12-5}{12+9} = \frac{7}{21} = \frac{1}{3} and 412=13\frac{4}{12} = \frac{1}{3}. The original equation holds true for x=12x = 12.
  11. Check x=3x = -3: Checking x=12x = 12: 12512+9=721=13\frac{12-5}{12+9} = \frac{7}{21} = \frac{1}{3} and 412=13\frac{4}{12} = \frac{1}{3}. The original equation holds true for x=12x = 12.Checking x=3x = -3: 353+9=86=43\frac{-3-5}{-3+9} = \frac{-8}{6} = \frac{-4}{3} and 43=43\frac{4}{-3} = \frac{-4}{3}. The original equation holds true for x=3x = -3.

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