Q. Solve for all values of x.x+9x−5=x4Answer: x=
Identify Equation: First, we need to identify the equation we are solving: (x−5)/(x+9)=(4)/(x). We want to find all values of x that satisfy this equation.
Cross-Multiply to Eliminate Fractions: To solve the equation, we will cross-multiply to eliminate the fractions: x - \(5) \times x = 4 \times (x + 9)\
Distribute and Simplify: Now, we distribute on both sides of the equation: x2−5x=4x+36.
Bring Terms Together: Next, we bring all terms to one side to set the equation to zero: x2−5x−4x−36=0.
Set Factors Equal to Zero: Now, we need to factor the quadratic equation, if possible, or use the quadratic formula to find the values of x. Let's try to factor first: (x−12)(x+3)=0.
Solve for x: We set each factor equal to zero and solve for x: x−12=0 or x+3=0.
Check for Extraneous Solutions: Solving the first equation gives us x=12. Solving the second equation gives us x=−3.
Check x=12: However, we must check for extraneous solutions by plugging these values back into the original equation, because the original equation has restrictions on the values of x (x cannot be 0 or −9, as these would make the denominators zero).
Check x=−3: Checking x=12: 12+912−5=217=31 and 124=31. The original equation holds true for x=12.
Check x=−3: Checking x=12: 12+912−5=217=31 and 124=31. The original equation holds true for x=12.Checking x=−3: −3+9−3−5=6−8=3−4 and −34=3−4. The original equation holds true for x=−3.
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