Q. Solve for all values of x.x+3x−5=x−1Answer: x=
Identify Equation: First, we need to identify the equation we are solving: (x−5)/(x+3)=(−1)/(x). We will solve for x by finding a common denominator and then cross-multiplying to eliminate the fractions.
Find Common Denominator: The common denominator between (x+3) and x is x(x+3). We will multiply both sides of the equation by this common denominator to clear the fractions.
Clear Fractions: Multiplying both sides of the equation by x(x+3), we get:(x+3x−5)⋅x(x+3)=(x−1)⋅x(x+3)This simplifies to:x(x−5)=−1(x+3)
Distribute and Simplify: Now we distribute on both sides of the equation: x2−5x=−x−3
Combine Like Terms: Next, we bring all terms to one side of the equation to set it equal to zero: x2−5x+x+3=0
Solve for x: Now we factor the quadratic equation:(x−3)(x−1)=0
Check Solutions: Set each factor equal to zero and solve for x:x−3=0 or x−1=0
Check Solutions: Set each factor equal to zero and solve for x:x−3=0 or x−1=0Solving each equation gives us the values of x:x=3 or x=1
Check Solutions: Set each factor equal to zero and solve for x:x−3=0 or x−1=0Solving each equation gives us the values of x:x=3 or x=1However, we must check these solutions against the original equation to ensure they do not make any denominator zero. The original equation has denominators (x+3) and x, so we must exclude any solutions where x=−3 or x=0.
Check Solutions: Set each factor equal to zero and solve for x:x−3=0 or x−1=0Solving each equation gives us the values of x:x=3 or x=1However, we must check these solutions against the original equation to ensure they do not make any denominator zero. The original equation has denominators (x+3) and x, so we must exclude any solutions where x=−3 or x=0.Checking the solutions, we see that neither x=3 nor x=1 makes any denominator zero, so both are valid solutions.
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