Solve for all values of x. (x+3)/(x-4)=(-5)/(x) Answer: x=

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Solve for all values of  x.  (x+3)/(x-4)=(-5)/(x) Answer:  x=

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Cross-multiply fractions: Cross-multiply to eliminate the fractions. (x + 3) * x = (-5) * (x - 4)Distribute equation sides: Distribute both sides of the equation. x^2 + 3x = -5x + 20Move terms set zero: Move all terms to one side to set the equation to zero. x^2 + 3x + 5x - 20 = 0Combine like terms: Combine like terms. x^2 + 8x - 20 = 0Factor quadratic equation: Factor the quadratic equation, if possible. However, the quadratic x^2 + 8x - 20 does not factor nicely. We will use the quadratic formula instead.Apply quadratic formula: Apply the quadratic formula. x = [-b ± sqrt(b^2 - 4ac)] / (2a), where a = 1, b = 8, and c = -20.Calculate discriminant: Calculate the discriminant (b^2 - 4ac). Discriminant = (8)^2 - 4(1)(-20) = 64 + 80 = 144Calculate solutions: Calculate the two solutions using the quadratic formula. x = [-8 ± sqrt(144)] / 2(1) x = [-8 ± 12] / 2Solve for x values: Solve for the two values of x. x = (-8 + 12) / 2 = 4 / 2 = 2 x = (-8 - 12) / 2 = -20 / 2 = -10Check extraneous solutions: Check for extraneous solutions by plugging the values back into the original equation. For x = 2: (2+3)/(2-4) = (-5)/2 5/(-2) = (-5)/2 -5/2 = -5/2 (Valid solution)  For x = -10: (-10+3)/(-10-4) = (-5)/(-10) -7/(-14) = 1/2 1/2 = 1/2 (Valid solution)  Both solutions are valid and do not create any undefined conditions in the original equation.

Solve for all values of $x$ . $\newline$ $\frac{x+3}{x-4}=\frac{-5}{x}$ $\newline$ Answer: $x=$

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Solve for all values of x x x.\newlinex+3x−4=−5x \frac{x+3}{x-4}=\frac{-5}{x} x−4x+3​=x−5​\newlineAnswer: x= x= x=

Solve for all values of $x$ . $\newline$ $\frac{x+3}{x-4}=\frac{-5}{x}$ $\newline$ Answer: $x=$