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Solve for all values of 
x :

4x^(2)(x-10)-(x-10)=0
Answer: 
x=

Solve for all values of x x :\newline4x2(x10)(x10)=0 4 x^{2}(x-10)-(x-10)=0 \newlineAnswer: x= x=

Full solution

Q. Solve for all values of x x :\newline4x2(x10)(x10)=0 4 x^{2}(x-10)-(x-10)=0 \newlineAnswer: x= x=
  1. Factor out common term: Factor out the common term (x10)(x-10) from the equation.\newlineThe equation is 4x2(x10)(x10)=04x^2(x-10) - (x-10) = 0. We can factor (x10)(x-10) out of both terms.\newline(x10)(4x21)=0(x-10)(4x^2 - 1) = 0
  2. Set first factor equal: Set each factor equal to zero and solve for xx.\newlineFirst, set the first factor equal to zero:\newlinex10=0x - 10 = 0\newlinex=10x = 10
  3. Set second factor equal: Set the second factor equal to zero and solve for xx.4x21=04x^2 - 1 = 0This is a difference of squares and can be factored further:(2x1)(2x+1)=0(2x - 1)(2x + 1) = 0
  4. Factor difference of squares: Set each factor of the difference of squares equal to zero and solve for xx.\newlineFirst, set the first factor equal to zero:\newline2x1=02x - 1 = 0\newline2x=12x = 1\newlinex=12x = \frac{1}{2}
  5. Solve for x: Set the second factor equal to zero and solve for x.\newline2x+1=02x + 1 = 0\newline2x=12x = -1\newlinex=12x = -\frac{1}{2}

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