Solve for a positive value of x. log_(3)(243)=x Answer:

Given Logarithmic Equation: We are given the logarithmic equation log_3(243) = x, which means 3 raised to what power equals 243. We need to find the value of x.Recognize Power of 3: Recognize that 243 is a power of 3. Specifically, 243 is 3 raised to the 5th power, since 3^5 = 243.Rewrite Equation: Since we know that 3^5 = 243, we can write the equation as log_3(3^5) = x.Simplify Using Property: Using the property of logarithms that log_b(b^a) = a, we can simplify the equation to 5 = x.Final Value of x: Therefore, the positive value of x that satisfies the equation is x = 5.

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Solve for a positive value of
x.

log_(3)(243)=x
Answer:

Solve for a positive value of $x$ . $\newline$ $\log _{3}(243)=x$ $\newline$ Answer:

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Q. Solve for a positive value of

x

\newline

\log _{3}(243)=x

\newline

Answer:

Given Logarithmic Equation: We are given the logarithmic equation $\log_3(243) = x$ , which means $3$ raised to what power equals $243$ . We need to find the value of $x$ .
Recognize Power of $3$ : Recognize that $243$ is a power of $3$ . Specifically, $243$ is $3$ raised to the $5$ th power, since $3^5 = 243$ .
Rewrite Equation: Since we know that $3^5 = 243$ , we can write the equation as $\log_3(3^5) = x$ .
Simplify Using Property: Using the property of logarithms that $\log_b(b^a) = a$ , we can simplify the equation to $5 = x$ .
Final Value of x: Therefore, the positive value of $x$ that satisfies the equation is $x = 5$ .