Solve for a. 6 + 5a ≤ 1 ______

Subtract 6 from both sides: Subtract 6 from both sides of the inequality to isolate the term containing a. 6 + 5a ≤ 1 5a ≤ 1 - 6 5a ≤ -5Divide by 5: Divide both sides of the inequality by 5 to solve for a. 5a ≤ -5 a ≤ -5 / 5 a ≤ -1Check solution: Check the solution by substituting a = -1 back into the original inequality to ensure it makes the inequality true. 6 + 5(-1) ≤ 1 6 - 5 ≤ 1 1 ≤ 1 Since 1 is equal to 1, the inequality holds true.

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Solve for $a$ . $6 + 5a \leq 1$

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Math Problems

Grade 8

Solve two-step inequalities

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Q. Solve for

a

6 + 5a \leq 1

Subtract $6$ from both sides: Subtract $6$ from both sides of the inequality to isolate the term containing $a$ . $6 + 5a \leq 1$ $5a \leq 1 - 6$ $5a \leq -5$
Divide by $5$ : Divide both sides of the inequality by $5$ to solve for $a$ . $5a \leq -5$ $a \leq -5 / 5$ $a \leq -1$
Check solution: Check the solution by substituting $a = -1$ back into the original inequality to ensure it makes the inequality true. $6 + 5(-1) \leq 1$ $6 - 5 \leq 1$ $1 \leq 1$ Since $1$ is equal to $1$ , the inequality holds true.