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Solve each equation.\newline3(x4)=2(2x+1)3(x-4)=2(-2x+1)

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Q. Solve each equation.\newline3(x4)=2(2x+1)3(x-4)=2(-2x+1)
  1. Distribute Numbers: Distribute the numbers outside the parentheses to the terms inside the parentheses.\newlineFor the left side of the equation, multiply 33 by both xx and 4-4.\newlineFor the right side of the equation, multiply 22 by both 2x-2x and 11.
  2. Perform Distribution: Perform the distribution from Step 11.\newlineLeft side: 3×x=3x3 \times x = 3x and 3×(4)=123 \times (-4) = -12, so we have 3x123x - 12.\newlineRight side: 2×(2x)=4x2 \times (-2x) = -4x and 2×1=22 \times 1 = 2, so we have 4x+2-4x + 2.\newlineNow the equation looks like this: 3x12=4x+23x - 12 = -4x + 2.
  3. Get Terms Together: Get all the xx terms on one side and the constant terms on the other side.\newlineTo do this, add 4x4x to both sides to move the xx terms to the left, and add 1212 to both sides to move the constants to the right.
  4. Perform Operations: Perform the operations from Step 33.\newlineAdding 4x4x to both sides gives us 3x+4x12=4x+4x+23x + 4x - 12 = -4x + 4x + 2, which simplifies to 7x12=27x - 12 = 2.\newlineAdding 1212 to both sides gives us 7x12+12=2+127x - 12 + 12 = 2 + 12, which simplifies to 7x=147x = 14.
  5. Solve for x: Solve for x by dividing both sides of the equation by 77.\newline7x=147x = 14\newlinex=147x = \frac{14}{7}\newlinex=2x = 2