Solve by substitution {:[3x-2y=14],[y=5x]:} A. (-2,-10) B. (-2,10) C. (2,-10) D. infinitely many solutions

Substitute Equations: Substitute the second equation into the first equation. Given the system of equations: 3x - 2y = 14 y = 5x Substitute y = 5x into the first equation: 3x - 2(5x) = 14Simplify and Solve: Simplify the equation and solve for x. 3x - 10x = 14 -7x = 14 Divide both sides by -7 to find x: x = 14 / -7 x = -2Find Value of y: Substitute the value of x back into the second equation to find y. y = 5x y = 5(-2) y = -10Write Ordered Pair: Write the solution as an ordered pair. The solution to the system of equations is x = -2 and y = -10. The ordered pair is (-2, -10).

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Solve by substitution $\newline$ $\begin{cases} 3x-2y=14 \ y=5x \end{cases}$ $\newline$ A. $(-2,-10)$ $\newline$ B. $(-2,10)$ $\newline$ C. $(2,-10)$ $\newline$ D. infinitely many solutions

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Q. Solve by substitution

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\begin{cases} 3x-2y=14 \ y=5x \end{cases}

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(-2,-10)

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(-2,10)

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(2,-10)

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D. infinitely many solutions

Substitute Equations: Substitute the second equation into the first equation. $\newline$ Given the system of equations: $\newline$ $3x - 2y = 14$ $\newline$ $y = 5x$ $\newline$ Substitute $y = 5x$ into the first equation: $\newline$ $3x - 2(5x) = 14$
Simplify and Solve: Simplify the equation and solve for $x$ . $3x - 10x = 14$ $-7x = 14$ Divide both sides by $-7$ to find $x$ : $x = \frac{14}{-7}$ $x = -2$
Find Value of y: Substitute the value of $x$ back into the second equation to find $y$ . $y = 5x$ $y = 5(-2)$ $y = -10$
Write Ordered Pair: Write the solution as an ordered pair. $\newline$ The solution to the system of equations is $x = -2$ and $y = -10$ . $\newline$ The ordered pair is $(-2, -10)$ .