Solve. 7(z+3)=28 Answer: z=

Distribute 7: Distribute the 7 to both terms inside the parentheses. We need to apply the distributive property, which states that a(b + c) = ab + ac. In this case, we have 7(z + 3), which becomes 7z + 7*3. 7(z + 3) = 7z + 21Set up equation: Set up the equation with the distributed terms. Now we have the equation 7z + 21 = 28.Subtract 21: Subtract 21 from both sides of the equation to isolate the term with the variable z. To solve for z, we need to get z by itself on one side of the equation. We do this by subtracting 21 from both sides. 7z + 21 - 21 = 28 - 21 This simplifies to: 7z = 7Divide by 7: Divide both sides of the equation by 7 to solve for z. To find the value of z, we divide both sides of the equation by 7. 7z / 7 = 7 / 7 This simplifies to: z = 1

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Solve. $\newline$ $7(z+3)=28$ $\newline$ Answer: $z=$

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Math Problems

Grade 7

Solve two-step equations with parentheses

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Q. Solve.

\newline

7(z+3)=28

\newline

Answer:

z=

Distribute $7$ : Distribute the $7$ to both terms inside the parentheses. $\newline$ We need to apply the distributive property, which states that $a(b + c) = ab + ac$ . In this case, we have $7(z + 3)$ , which becomes $7z + 7\times3$ . $\newline$ $7(z + 3) = 7z + 21$
Set up equation: Set up the equation with the distributed terms. $\newline$ Now we have the equation $7z + 21 = 28$ .
Subtract $21$ : Subtract $21$ from both sides of the equation to isolate the term with the variable $z$ . To solve for $z$ , we need to get $z$ by itself on one side of the equation. We do this by subtracting $21$ from both sides. $7z + 21 - 21 = 28 - 21$ This simplifies to: $7z = 7$
Divide by $7$ : Divide both sides of the equation by $7$ to solve for $z$ . $\newline$ To find the value of $z$ , we divide both sides of the equation by $7$ . $\newline$ $\frac{7z}{7} = \frac{7}{7}$ $\newline$ This simplifies to: $\newline$ $z = 1$