Solve. 7(z+2)=49 Answer: z=

Identify equation: Identify the equation to solve. We are given the equation 7(z+2)=49, which is a linear equation.Divide to isolate term: Divide both sides of the equation by 7 to isolate the term (z+2). Doing this, we get (z+2) = 49 / 7.Calculate division: Calculate the division on the right side of the equation. 49 divided by 7 equals 7, so the equation simplifies to (z+2) = 7.Subtract to solve for z: Subtract 2 from both sides of the equation to solve for z. Subtracting 2 from both sides gives us z = 7 - 2.Calculate subtraction: Calculate the subtraction on the right side of the equation. 7 minus 2 equals 5, so the value of z is 5.

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Math Problems

Grade 7

Solve two-step equations with parentheses

Full solution

Q. Solve.

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7(z+2)=49

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Answer:

z=

Identify equation: Identify the equation to solve. $\newline$ We are given the equation $7(z+2)=49$ , which is a linear equation.
Divide to isolate term: Divide both sides of the equation by $7$ to isolate the term $(z+2)$ . Doing this, we get (z+2) = rac{49}{7}.
Calculate division: Calculate the division on the right side of the equation. $49$ divided by $7$ equals $7$ , so the equation simplifies to $(z+2) = 7$ .
Subtract to solve for $z$ : Subtract $2$ from both sides of the equation to solve for $z$ . Subtracting $2$ from both sides gives us $z = 7 - 2$ .
Calculate subtraction: Calculate the subtraction on the right side of the equation. $7 - 2 = 5$ , so the value of $z$ is $5$ .