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7(z-2)=28
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z=
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Solve.\newline7(z2)=28 7(z-2)=28 \newlineAnswer: z= z= \newlineSubmit Answer

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Q. Solve.\newline7(z2)=28 7(z-2)=28 \newlineAnswer: z= z= \newlineSubmit Answer
  1. Distribute 77 to terms: Distribute the 77 to both terms inside the parentheses.\newlineWe need to apply the distributive property, which states that a(b+c)=ab+aca(b + c) = ab + ac. In this case, we have 7(z2)7(z - 2), which becomes 7z727\cdot z - 7\cdot 2.\newlineCalculation: 7z14=287z - 14 = 28
  2. Add 1414 to both sides: Add 1414 to both sides of the equation to isolate the term with the variable zz. We want to get zz by itself on one side of the equation, so we need to undo the subtraction of 1414 by adding 1414 to both sides. Calculation: 7z14+14=28+147z - 14 + 14 = 28 + 14, which simplifies to 7z=427z = 42
  3. Divide by 77: Divide both sides of the equation by 77 to solve for zz. Now that we have 7z=427z = 42, we can find zz by dividing both sides by 77. Calculation: 7z7=427\frac{7z}{7} = \frac{42}{7}, which simplifies to z=6z = 6