Solve. 3(z+6)=33 Answer: z=

Distribute Terms: Distribute the 3 to both terms inside the parentheses. We need to apply the distributive property, which states that a(b + c) = ab + ac. In this case, we distribute 3 to both z and 6. 3(z) + 3(6) = 33 3z + 18 = 33Subtract 18: Subtract 18 from both sides of the equation to isolate the term with the variable z. To solve for z, we need to get z on one side of the equation by itself. We do this by subtracting 18 from both sides. 3z + 18 - 18 = 33 - 18 3z = 15Divide by 3: Divide both sides of the equation by 3 to solve for z. Now that we have 3z = 15, we divide both sides by 3 to find the value of z. 3z / 3 = 15 / 3 z = 5

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Math Problems

Grade 7

Solve two-step equations with parentheses

Full solution

Q. Solve.

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3(z+6)=33

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Answer:

z=

Distribute Terms: Distribute the $3$ to both terms inside the parentheses. $\newline$ We need to apply the distributive property, which states that $a(b + c) = ab + ac$ . In this case, we distribute $3$ to both $z$ and $6$ . $\newline$ $3(z) + 3(6) = 33$ $\newline$ $3z + 18 = 33$
Subtract $18$ : Subtract $18$ from both sides of the equation to isolate the term with the variable $z$ . To solve for $z$ , we need to get $z$ on one side of the equation by itself. We do this by subtracting $18$ from both sides. $3z + 18 - 18 = 33 - 18$ $3z = 15$
Divide by $3$ : Divide both sides of the equation by $3$ to solve for $z$ . Now that we have $3z = 15$ , we divide both sides by $3$ to find the value of $z$ . $\frac{3z}{3} = \frac{15}{3}$ $z = 5$