Solve. 3(3z+5)=33 Answer: z=

Distribute 3: Distribute the 3 across the terms inside the parentheses. We need to multiply 3 by each term inside the parentheses (3z and 5). This gives us 3 * 3z + 3 * 5, which simplifies to 9z + 15. So the equation becomes 9z + 15 = 33.Subtract 15: Subtract 15 from both sides of the equation to isolate the term with the variable z. We want to get z by itself on one side of the equation, so we need to remove the constant term from the left side. Subtracting 15 from both sides gives us 9z + 15 - 15 = 33 - 15, which simplifies to 9z = 18.Divide by 9: Divide both sides of the equation by 9 to solve for z. To find the value of z, we divide both sides of the equation by 9. This gives us 9z / 9 = 18 / 9, which simplifies to z = 2.

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Math Problems

Grade 7

Solve two-step equations with parentheses

Full solution

Q. Solve.

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3(3 z+5)=33

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Answer:

z=

Distribute $3$ : Distribute the $3$ across the terms inside the parentheses. $\newline$ We need to multiply $3$ by each term inside the parentheses ( $3z$ and $5$ ). $\newline$ This gives us $3 \times 3z + 3 \times 5$ , which simplifies to $9z + 15$ . $\newline$ So the equation becomes $9z + 15 = 33$ .
Subtract $15$ : Subtract $15$ from both sides of the equation to isolate the term with the variable $z$ . We want to get $z$ by itself on one side of the equation, so we need to remove the constant term from the left side. Subtracting $15$ from both sides gives us $9z + 15 - 15 = 33 - 15$ , which simplifies to $9z = 18$ .
Divide by $9$ : Divide both sides of the equation by $9$ to solve for $z$ . To find the value of $z$ , we divide both sides of the equation by $9$ . This gives us $\frac{9z}{9} = \frac{18}{9}$ , which simplifies to $z = 2$ .