Solve. 2(7y+3)=34 Answer: y=

Distribute Terms: Distribute the 2 across the terms inside the parentheses. We need to apply the distributive property, which states that a(b + c) = ab + ac. In this case, we have 2(7y + 3), which becomes 2*7y + 2*3. This simplifies to 14y + 6.Set Up Equation: Set up the equation with the distributed terms. The equation now looks like this: 14y + 6 = 34.Subtract Constant: Subtract 6 from both sides of the equation to isolate the term with the variable y. We want to get y by itself on one side of the equation, so we need to remove the constant term from the left side. We do this by subtracting 6 from both sides. 14y + 6 - 6 = 34 - 6, which simplifies to 14y = 28.Divide to Solve: Divide both sides of the equation by 14 to solve for y. To find the value of y, we divide both sides of the equation by 14. 14y / 14 = 28 / 14, which simplifies to y = 2.

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Solve. $\newline$ $2(7 y+3)=34$ $\newline$ Answer: $y=$

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Math Problems

Grade 7

Solve two-step equations with parentheses

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Q. Solve.

\newline

2(7 y+3)=34

\newline

Answer:

y=

Distribute Terms: Distribute the $2$ across the terms inside the parentheses. $\newline$ We need to apply the distributive property, which states that $a(b + c) = ab + ac$ . In this case, we have $2(7y + 3)$ , which becomes $2\times7y + 2\times3$ . $\newline$ This simplifies to $14y + 6$ .
Set Up Equation: Set up the equation with the distributed terms. $\newline$ The equation now looks like this: $14y + 6 = 34$ .
Subtract Constant: Subtract $6$ from both sides of the equation to isolate the term with the variable $y$ . We want to get $y$ by itself on one side of the equation, so we need to remove the constant term from the left side. We do this by subtracting $6$ from both sides. $14y + 6 - 6 = 34 - 6$ , which simplifies to $14y = 28$ .
Divide to Solve: Divide both sides of the equation by $14$ to solve for $y$ . To find the value of $y$ , we divide both sides of the equation by $14$ . $\frac{14y}{14} = \frac{28}{14}$ , which simplifies to $y = 2$ .