Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Simplify 
e^(ln 2-ln 4) and write without any logarithms.
Answer:

Simplify eln2ln4 e^{\ln 2-\ln 4} and write without any logarithms.\newlineAnswer:

Full solution

Q. Simplify eln2ln4 e^{\ln 2-\ln 4} and write without any logarithms.\newlineAnswer:
  1. Understand Properties: Understand the properties of logarithms and exponents.\newlineThe expression e(ln2ln4)e^{(\ln 2 - \ln 4)} involves the natural logarithm, ln\ln, and the natural exponential function, ee. The natural logarithm ln(x)\ln(x) is the inverse function of the exponential function exe^x. Therefore, e(lnx)=xe^{(\ln x)} = x for any positive number xx. Also, the difference of logarithms ln(a)ln(b)\ln(a) - \ln(b) is equivalent to the logarithm of the division of aa by bb, ln\ln00. We will use these properties to simplify the expression.
  2. Combine Logarithms: Apply the logarithm property to combine the logarithms.\newlineUsing the property that ln(a)ln(b)=ln(ab)\ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right), we can rewrite the exponent as a single logarithm:\newlineeln2ln4=eln(24)e^{\ln 2 - \ln 4} = e^{\ln(\frac{2}{4})}.
  3. Simplify Fraction: Simplify the fraction inside the logarithm.\newlineThe fraction 24\frac{2}{4} can be simplified to 12\frac{1}{2}, so we have:\newlineeln(24)=eln(12)e^{\ln(\frac{2}{4})} = e^{\ln(\frac{1}{2})}.
  4. Apply Inverse Property: Apply the inverse property of logarithms and exponents.\newlineUsing the property that elnx=xe^{\ln x} = x, we can simplify the expression to get the final result:\newlineeln(12)=12e^{\ln(\frac{1}{2})} = \frac{1}{2}.

More problems from Find the roots of factored polynomials