Shelley's cup of tea cooled down 1/2 of a degree in 10 seconds. At what rate is her tea cooling down? Simplify your answer and write it as a proper fraction, mixed number, or whole number. ____ degrees per second

Identify Change: Identify the change in temperature and the time taken. Temperature change = 1/2 degree Time taken = 10 seconds We need to find the rate of cooling, which is the temperature change per unit of time.Calculate Rate: Calculate the rate of cooling using the formula: Rate of cooling = Temperature change ÷ Time taken Rate of cooling = (1/2) ÷ 10Simplify Expression: Simplify the expression to find the rate. (1/2) ÷ 10 = 1/2 × 1/10 = 1/20 So, the tea is cooling down at a rate of 1/20 degrees per second.

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Shelley's cup of tea cooled down $\frac{1}{2}$ of a degree in $10$ seconds. At what rate is her tea cooling down? $\newline$ Simplify your answer and write it as a proper fraction, mixed number, or whole number. $\newline$ ____ degrees per second $\newline$

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Math Problems

Grade 7

Calculate unit rates with fractions

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Q. Shelley's cup of tea cooled down

\frac{1}{2}

of a degree in

10

seconds. At what rate is her tea cooling down?

\newline

Simplify your answer and write it as a proper fraction, mixed number, or whole number.

\newline

____ degrees per second

\newline

Identify Change: Identify the change in temperature and the time taken. $\newline$ Temperature change = $\frac{1}{2}$ degree $\newline$ Time taken = $10$ seconds $\newline$ We need to find the rate of cooling, which is the temperature change per unit of time.
Calculate Rate: Calculate the rate of cooling using the formula: $\newline$ Rate of cooling = Temperature change $\div$ Time taken $\newline$ Rate of cooling = $(\frac{1}{2}) \div 10$
Simplify Expression: Simplify the expression to find the rate. $\newline$ $(1/2) \div 10 = \frac{1}{2} \times \frac{1}{10} = \frac{1}{20}$ $\newline$ So, the tea is cooling down at a rate of $\frac{1}{20}$ degrees per second.