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$Shelley's cup of tea cooled down (1)/(2) of a degree in 10 seconds. At what rate is her tea cooling down? Simplify your answer and write it as a proper fraction, mixed number, or whole number. degrees per second$

Shelley's cup of tea cooled down $\frac{1}{2}$ of a degree in $10$ seconds. At what rate is her tea cooling down? $\newline$ Simplify your answer and write it as a proper fraction, mixed number, or whole number. _______degrees per second

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Calculate unit rates with fractions

Full solution

Q. Shelley's cup of tea cooled down

\frac{1}{2}

of a degree in

10

seconds. At what rate is her tea cooling down?

\newline

Simplify your answer and write it as a proper fraction, mixed number, or whole number. _______degrees per second

Given Information: We have: $\newline$ Temperature decrease = $\frac{1}{2}$ degree $\newline$ Time = $10$ seconds $\newline$ Which formula should we use to calculate the rate of cooling? $\newline$ Rate of cooling = Temperature decrease $\div$ Time
Formula for Rate of Cooling: We have: $\newline$ Temperature decrease = $\frac{1}{2}$ degree $\newline$ Time = $10$ seconds $\newline$ Which expression should we use to calculate the rate of cooling? $\newline$ Rate of cooling = Temperature decrease $\div$ Time $\newline$ Rate of cooling = $(\frac{1}{2}) \div 10$
Expression for Rate of Cooling: Simplify $(\frac{1}{2}) \div 10$ . $\newline$ $(\frac{1}{2}) \div 10 = (\frac{1}{2}) \times (\frac{1}{10}) = \frac{1}{(2\times10)} = \frac{1}{20}$ $\newline$ The rate at which Shelley's cup of tea is cooling down is $\frac{1}{20}$ of a degree per second.

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