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Sharon read a 300-page book. She read at a rate of 15 pages per day in 
d days.
Write an equation to describe this situation.

Sharon read a 300300-page book. She read at a rate of 1515 pages per day in d d days.\newlineWrite an equation to describe this situation.

Full solution

Q. Sharon read a 300300-page book. She read at a rate of 1515 pages per day in d d days.\newlineWrite an equation to describe this situation.
  1. Identify variables and constants: Identify the variables and constants in the situation.\newlineSharon reads a 300300-page book, so the total number of pages is a constant, 300300 pages.\newlineShe reads at a rate of 1515 pages per day, so the rate is another constant, 1515 pages/day.\newlineThe number of days she reads is the variable we are looking for, represented by dd.
  2. Set up equation: Set up the equation based on the given information.\newlineWe know that the total number of pages read is equal to the rate of reading per day multiplied by the number of days.\newlineSo, the equation is: Total Pages == Rate ×\times Days\newlineIn this case, it translates to: 300=15×d300 = 15 \times d
  3. Check for errors: Check the equation for any mathematical errors.\newlineThe equation 300=15×d300 = 15 \times d correctly represents the situation where the total number of pages read (300300) is the product of the rate of reading (1515 pages/day) and the number of days (dd).