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Select the answer which is equivalent to the given expression using your calculator.

log_(49)343

(3)/(2)

(2)/(5)

(2)/(3)

(5)/(2)

Select the answer which is equivalent to the given expression using your calculator.\newlinelog49343 \log _{49} 343 \newline32 \frac{3}{2} \newline25 \frac{2}{5} \newline23 \frac{2}{3} \newline52 \frac{5}{2}

Full solution

Q. Select the answer which is equivalent to the given expression using your calculator.\newlinelog49343 \log _{49} 343 \newline32 \frac{3}{2} \newline25 \frac{2}{5} \newline23 \frac{2}{3} \newline52 \frac{5}{2}
  1. Recognize Relationship: We need to evaluate the expression log49343\log_{49}343. To do this, we can use the change of base formula for logarithms, which states that logab\log_{a}b can be written as log(b)log(a)\frac{\log(b)}{\log(a)}, where log\log denotes the common logarithm. However, since we are dealing with specific numbers, we can look for a relationship between the base and the number.
  2. Rewrite Using Properties: We recognize that 4949 is a power of 77, specifically 727^2, and 343343 is also a power of 77, specifically 737^3. This can be written as 49=7249 = 7^2 and 343=73343 = 7^3.
  3. Apply Power Rule: Using the property of logarithms that logaak=k\log_{a} a^{k} = k, we can rewrite log49343\log_{49}343 as log72(73)\log_{7^2}(7^3). According to the power rule of logarithms, which states that logabk=klogab\log_{a} b^{k} = k \cdot \log_{a} b, we can simplify this expression.
  4. Apply Power Rule: Using the property of logarithms that logaak=k\log_{a} a^{k} = k, we can rewrite log(49)343\log_{(49)}343 as log(72)(73)\log_{(7^2)}(7^3). According to the power rule of logarithms, which states that logabk=klogab\log_{a} b^{k} = k \cdot \log_{a} b, we can simplify this expression.Applying the power rule, we get log(72)(73)=32\log_{(7^2)}(7^3) = \frac{3}{2}, because we are taking the logarithm of a cube (343343 is 77 cubed) with respect to the square of the same base (4949 is 77 squared).

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