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Select all of the equations below that are equivalent to:\newline85=bc85 = bc\newlineUse properties of equality.\newlineMulti-select Choices:\newline(A) 5=bc175 = \frac{bc}{17}\newline(B) 5=bc17–5 = \frac{bc}{–17}\newline(C) 18=bc5–18 = \frac{bc}{–5}\newline(D) 17=bc517 = \frac{bc}{5}

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Q. Select all of the equations below that are equivalent to:\newline85=bc85 = bc\newlineUse properties of equality.\newlineMulti-select Choices:\newline(A) 5=bc175 = \frac{bc}{17}\newline(B) 5=bc17–5 = \frac{bc}{–17}\newline(C) 18=bc5–18 = \frac{bc}{–5}\newline(D) 17=bc517 = \frac{bc}{5}
  1. Analyze Equation Properties: First, let's analyze the original equation and the properties of equality we can use to create equivalent equations. The original equation is 85=bc85 = bc. We can multiply or divide both sides of the equation by the same non-zero number to maintain equality.
  2. Check Option (A): Let's check option (A) 5=bc175 = \frac{bc}{17}. To see if this is equivalent to the original equation, we can multiply both sides of the original equation by 117\frac{1}{17}. \newline85×(117)=bc×(117)85 \times \left(\frac{1}{17}\right) = bc \times \left(\frac{1}{17}\right)\newline5=bc175 = \frac{bc}{17}\newlineThis shows that option (A) is equivalent to the original equation.
  3. Check Option (B): Now, let's check option (B) 5=bc17–5 = \frac{bc}{–17}. To see if this is equivalent to the original equation, we can multiply both sides of the original equation by 117-\frac{1}{17}.85×(117)=bc×(117)85 \times \left(-\frac{1}{17}\right) = bc \times \left(-\frac{1}{17}\right)5=bc17-5 = \frac{bc}{–17}This shows that option (B) is equivalent to the original equation.
  4. Check Option (C): Next, let's check option (C) 18=bc5-18 = \frac{bc}{-5}. To see if this is equivalent to the original equation, we can multiply both sides of the original equation by 15-\frac{1}{5}.\newline85×(15)=bc×(15)85 \times (-\frac{1}{5}) = bc \times (-\frac{1}{5})\newline17=bc5-17 = \frac{bc}{-5}\newlineThis shows that option (C) is not equivalent to the original equation because 17-17 is not equal to 18-18.
  5. Check Option (D): Finally, let's check option (D) 17=bc517 = \frac{bc}{5}. To see if this is equivalent to the original equation, we can multiply both sides of the original equation by 15\frac{1}{5}. \newline85×(15)=bc×(15)85 \times \left(\frac{1}{5}\right) = bc \times \left(\frac{1}{5}\right)\newline17=bc517 = \frac{bc}{5}\newlineThis shows that option (D) is equivalent to the original equation.

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