Find the missing coordinate to complete the ordered-pair solution to the given linear equation. 5x-4y=27 (a) (-1, ___) (b) (___,2) (a) The ordered-pair solution is (-1, ◻) (b) The ordered-pair solution is (◻,2)

Substitute x into equation: Plug x = -1 into the equation to find y. 5(-1) - 4y = 27 -5 - 4y = 27Add 5 to both sides: Add 5 to both sides to isolate the term with y. -4y = 27 + 5 -4y = 32Divide by -4 for y: Divide both sides by -4 to solve for y. y = 32 / -4 y = -8Substitute y into equation: Now, plug y = 2 into the equation to find x. 5x - 4(2) = 27 5x - 8 = 27Add 8 to both sides: Add 8 to both sides to isolate the term with x. 5x = 27 + 8 5x = 35Divide by 5 for x: Divide both sides by 5 to solve for x. x = 35 / 5 x = 7

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Find the missing coordinate to complete the ordered-pair solution to the given linear equation.
5x-4y=27
(a) (-1, ___)
(b) (___,2)
(a) The ordered-pair solution is (-1, ◻)
(b) The ordered-pair solution is (◻,2)

Find the missing coordinate to complete the ordered-pair solution to the given linear equation. $\newline$ $5 x-4 y=27$ $\newline$ (a) $(-1$ , _) $\newline$ (b) (_ $, 2)$ $\newline$ (a) The ordered-pair solution is $(-1, \square)$ $\newline$ (b) The ordered-pair solution is $( \square, 2)$

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Q. Find the missing coordinate to complete the ordered-pair solution to the given linear equation.

\newline

5 x-4 y=27

\newline

(a)

(-1

, ___)

\newline

(b) (___

, 2)

\newline

(a) The ordered-pair solution is

(-1, \square)

\newline

(b) The ordered-pair solution is

( \square, 2)

Substitute $x$ into equation: Plug $x = -1$ into the equation to find $y$ . $\newline$ $5(-1) - 4y = 27$ $\newline$ $-5 - 4y = 27$
Add $5$ to both sides: Add $5$ to both sides to isolate the term with $y$ . $-4y = 27 + 5$ $-4y = 32$
Divide by $-4$ for $y$ : Divide both sides by $-4$ to solve for $y$ . $\newline$ $y = \frac{32}{-4}$ $\newline$ $y = -8$
Substitute $y$ into equation: Now, plug $y = 2$ into the equation to find $x$ . $\newline$ $5x - 4(2) = 27$ $\newline$ $5x - 8 = 27$
Add $8$ to both sides: Add $8$ to both sides to isolate the term with $x$ . $\newline$ $5x = 27 + 8$ $\newline$ $5x = 35$
Divide by $5$ for $x$ : Divide both sides by $5$ to solve for $x$ . $x = \frac{35}{5}$ $x = 7$