Elimination Method: First, let's solve the system of equations using the elimination method.We have the system:1) −x−5y+z=172) −5x−5y+5z=53) 2x+5y−3z=−10Let's start by eliminating y from equations 1 and 3 by adding them together.
Equation 4: Adding equation 1 and equation 3:(−x−5y+z)+(2x+5y−3z)=17+(−10)This simplifies to:−x+2x−5y+5y+z−3z=7Which further simplifies to:x−2z=7Let's call this equation 4.
Equation 5: Now, let's eliminate y from equations 2 and 3 by multiplying equation 3 by −1 and adding it to equation 2.Multiplying equation 3 by −1 gives us:−2x−5y+3z=10Let's call this equation 5.
Equation 6: Adding equation 2 and equation 5:(−5x−5y+5z)+(−2x−5y+3z)=5+10This simplifies to:−5x−2x−5y−5y+5z+3z=15Which further simplifies to:−7x+8z=15Let's call this equation 6.
Equation 7: Now we have two equations with two variables (equations 4 and 6):4) x−2z=76) −7x+8z=15Let's multiply equation 4 by 7 to help eliminate x:7(x−2z)=7(7)7x−14z=49Let's call this equation 7.
Value of z: Adding equation 6 and equation 7:(−7x+8z)+(7x−14z)=15+49This simplifies to:−7x+7x+8z−14z=64Which further simplifies to:−6z=64Dividing both sides by −6 gives us:z=−664z=−332
Substitute for x: Now that we have the value of z, we can substitute it back into equation 4 to find x:x−2(−332)=7x+364=7To solve for x, we need to subtract 364 from both sides:x=7−364x=(321−64)x=−343
Find y using Equation 1: Now we have the values for x and z. We can substitute these into any of the original equations to find y. Let's use equation 1:−x−5y+z=17−(−43/3)−5y+(−32/3)=1743/3−5y−32/3=17Combining like terms gives us:11/3−5y=17To solve for y, we need to subtract 11/3 from both sides and then divide by x0:x1x2x3x4x5x6
Substitution Method: Now let's solve the system using the substitution method.We will start by expressing x from equation 1 in terms of y and z:−x−5y+z=17x=−5y+z−17Let's call this equation 8.
Incorrect Substitution: Next, we substitute equation 8 into equation 2:−5(−5y+z−17)−5y+5z=5This simplifies to:25y−5z+85−5y+5z=5Which further simplifies to:20y+85=5Subtracting 85 from both sides gives us:20y=−80Dividing both sides by 20 gives us:y=−4However, this is a math error because we did not substitute correctly. We should have substituted for x in all terms of equation 2, not just the first term.