Rumplane-Citu New tab ×+ 8267 4sqrt5 In a pasture are horses and chickens if there are a total of 28 animals and 80leg : how many chickens and horses? 12 horses, 16 16 horses, 12 18 horses, 10 chickens chickens chickens 10 horses, 18 chickens janio 는 180 (Yeo here tio warch

Identify variables: Identify the variables: Let $ h $ represent the number of horses and $ c $ represent the number of chickens. Set up equations: Set up the equations based on the total number of animals and the total number of legs: 1. $ h + c = 28 $ (total animals) 2. $ 4h + 2c = 80 $ (total legs) Solve for c: Solve the first equation for one of the variables. Let's solve for $ c $: $ c = 28 - h $ Substitute c: Substitute $ c = 28 - h $ into the second equation: $ 4h + 2(28 - h) = 80 $ Simplify and solve: Simplify and solve for $ h $: $ 4h + 56 - 2h = 80 $ $ 2h + 56 = 80 $ $ 2h = 24 $ $ h = 12 $ Substitute h: Substitute $ h = 12 $ back into the equation for $ c $: $ c = 28 - 12 $ $ c = 16 $

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Rumplane-Citu
New tab

×+
8267

4sqrt5
In a pasture are horses and chickens if there are a total of 28 animals and
80leg : how many chickens and horses?
12 horses, 16
16 horses, 12
18 horses, 10 chickens chickens chickens
10 horses, 18 chickens
janio
는
180
(Yeo here tio warch

In a pasture are horses and chickens if there are a total of $28$ animals and $80$ legs: how many chickens and horses? $\newline$ $12$ horses, $16$ chickens $\newline$ $16$ horses, $12$ chickens $\newline$ $18$ horses, $10$ chickens $\newline$ $10$ horses, $18$ chickens

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Q. In a pasture are horses and chickens if there are a total of

28

animals and

80

legs: how many chickens and horses?

\newline

12

horses,

16

chickens

\newline

16

horses,

12

chickens

\newline

18

horses,

10

chickens

\newline

10

horses,

18

chickens

Identify variables: Identify the variables: Let $h$ represent the number of horses and $c$ represent the number of chickens.
Set up equations: Set up the equations based on the total number of animals and the total number of legs: $\newline$ $1$ . $h + c = 28$ (total animals) $\newline$ $2$ . $4h + 2c = 80$ (total legs)
Solve for c: Solve the first equation for one of the variables. Let's solve for $c$ : $\newline$ $c = 28 - h$
Substitute c: Substitute $c = 28 - h$ into the second equation: $\newline$ $4h + 2(28 - h) = 80$
Simplify and solve: Simplify and solve for $h$ : $\newline$ $4h + 56 - 2h = 80$ $\newline$ $2h + 56 = 80$ $\newline$ $2h = 24$ $\newline$ $h = 12$
Substitute h: Substitute $h = 12$ back into the equation for $c$ : $\newline$ $c = 28 - 12$ $\newline$ $c = 16$