Ricardo has two types of assignments for his class. The number of mini assignments, m, he has is 1 fewer than twice the number of long assignments, l, he has. If he has 46 assignments in total, which of the following systems of equations can be used to correctly solve for m and l ? Choose 1 answer: (A) m=2l-1 m+l=46 (B) m=2l-1 m=l+46 (C) l=2m-1 m+l=46 (D) l=2m-1 m=l+46

Question

Ricardo has two types of assignments for his class. The number of mini assignments,  m, he has is 1 fewer than twice the number of long assignments,  l, he has. If he has 46 assignments in total, which of the following systems of equations can be used to correctly solve for  m and  l ? Choose 1 answer: (A)  m=2l-1  m+l=46 (B)  m=2l-1  m=l+46 (C)  l=2m-1  m+l=46 (D)  l=2m-1  m=l+46

Bytelearn · Accepted Answer

Write Equations:  Step 1: Let's write down what we know. Ricardo has mini assignments (m) and long assignments (l). The problem says that the number of mini assignments is 1 fewer than twice the number of long assignments. So we can write the first equation as m = 2l - 1. Total Assignments:  Step 2: The total number of assignments is 46. This means that if we add the number of mini assignments and the number of long assignments, we should get 46. So the second equation is m + l = 46. Check Options:  Step 3: Now we need to find which answer choice matches our two equations. Let's check each option. Option (A) Verification:  Step 4: Option (A) says m = 2l - 1 and m + l = 46. This matches our equations from Step 1 and Step 2. Other Options Check:  Step 5: Let's check the other options just to be sure. Option (B) says m = 2l - 1 and m = l + 46. This doesn't make sense because it suggests that m is equal to two different things. Incorrect Options:  Step 6: Option (C) says l = 2m - 1 and m + l = 46. This is not what we have because our first equation is about m in terms of l, not the other way around. Correct Answer:  Step 7: Option (D) says l = 2m - 1 and m = l + 46. Again, this doesn't match our equations.  Step 8: So, the correct answer is the one that matches our equations from Step 1 and Step 2, which is Option (A).

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